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p=5x"
√p/5= x
jdi g-1(x)=√x/5
g-1(25) √25/5= √5
5x^2 = y
x^2 = y/5
x = ±√(y/5)
g^-1(x) = ± √(x/5)
g^-1(25) = ± √(25/5) = ± √5
Jadi nilai g^-1(25) = -√5 atau g^-1(25) = √5