Bantu dong jwb soal gue nih please. mtk
Jika b>0 dan
b
∫ (2x-3) dx = 12, maka nilai b = 12
1
Jika b>0 dan
b
∫ (2x-3) dx = 12, maka nilai b = 12
1
Takamori37
![\int_1^b 2x-3\, dx=12 \\ x^2-3x]_1^b=12 \\ (b^2-3b)-(1^2-3.1)=12 \\ b^2-3b-(1-3)=12 \\ b^2-3b+2=12 \\ b^2-3b-10=0 \\ (b+2)(b-5)=0 \\ b =-2$ (Diminta $b>0) \\ $Maka,$ \\ \boxed{b=5}](https://tex.z-dn.net/?f=%5Cint_1%5Eb+2x-3%5C%2C+dx%3D12+%5C%5C+x%5E2-3x%5D_1%5Eb%3D12+%5C%5C+%28b%5E2-3b%29-%281%5E2-3.1%29%3D12+%5C%5C+b%5E2-3b-%281-3%29%3D12+%5C%5C+b%5E2-3b%2B2%3D12+%5C%5C+b%5E2-3b-10%3D0+%5C%5C+%28b%2B2%29%28b-5%29%3D0+%5C%5C+b+%3D-2%24+%28Diminta+%24b%3E0%29+%5C%5C+%24Maka%2C%24+%5C%5C+%5Cboxed%7Bb%3D5%7D "\int_1^b 2x-3\, dx=12 \\ x^2-3x]_1^b=12 \\ (b^2-3b)-(1^2-3.1)=12 \\ b^2-3b-(1-3)=12 \\ b^2-3b+2=12 \\ b^2-3b-10=0 \\ (b+2)(b-5)=0 \\ b =-2$ (Diminta $b>0) \\ $Maka,$ \\ \boxed{b=5}")
0 votes
Thanks 0
More Questions From This User See All