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jdnya kan
x² - 3x dengan batas b sama 1 ya = 12
(b² - 3b) - ( 1 - 3) = 12 --> jd batas batasnya masukkin ke persamaan itu
(b² - 3b ) + 2 = 12
b² - 3b - 10 = 0
(b - 5) (b + 2) =0
jadi nilai bnya itu, b = 5 atau b = -2
itu jawabanku :)