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x²+ax/bx-2 = m+2/m-1
(m-2)(x²+ax)=(m+2)(bx-2)
(m-2)x²+a(m-2)x=b(m+1)x-2(m+2)
(m-2)x²+{a(m-2)-b(m+2)}x+2(m+2)=0
akar persamaan kuadrat akan berlawanan jika koefisien x bernilai 0(nol)
{a(m-2)-b(m+2)}=0
am-2a-bm-2b=0
m(a-b)=2(a+b)
m=2(a+b)/a-b
jawabannya B