Explicación:
1)
Datos
m = 1.5 Kg = 1500 g
Ce = 0.09 cal/g°C
To = 40°C
T = 70°C
Q = ?
Q = m.Ce.(T - To)
Q = 1500g ×0.09 cal/g°C × (125 - 25)
Q = 1500g ×0.09 cal/g°C × 100 °C
Q = 13 500 cal.
2)
AGUA
m = 1000 g
Ce = 1 cal/g°C
To = 40 °C
T = 70 °C
Q = 1000g ×1 cal/g°C × (70 - 40)
Q = 1000g × 1 cal/g°C × 30°C
Q = 30 000 cal.
HIERRO
Ce = 0.12 cal/g°C
Q = 1000g ×0.12 cal/g°C × (70 - 40)
Q = 1000g ×0.12 cal/g°C × 30 °C
Q = 3 600cal.
la cantidad de calor necesaria para aumentar la temperatura del agua es mayor que la del hierro
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Explicación:
1)
Datos
m = 1.5 Kg = 1500 g
Ce = 0.09 cal/g°C
To = 40°C
T = 70°C
Q = ?
Q = m.Ce.(T - To)
Q = 1500g ×0.09 cal/g°C × (125 - 25)
Q = 1500g ×0.09 cal/g°C × 100 °C
Q = 13 500 cal.
2)
AGUA
Datos
m = 1000 g
Ce = 1 cal/g°C
To = 40 °C
T = 70 °C
Q = ?
Q = m.Ce.(T - To)
Q = 1000g ×1 cal/g°C × (70 - 40)
Q = 1000g × 1 cal/g°C × 30°C
Q = 30 000 cal.
HIERRO
Datos
m = 1000 g
Ce = 0.12 cal/g°C
To = 40 °C
T = 70 °C
Q = ?
Q = m.Ce.(T - To)
Q = 1000g ×0.12 cal/g°C × (70 - 40)
Q = 1000g ×0.12 cal/g°C × 30 °C
Q = 3 600cal.
la cantidad de calor necesaria para aumentar la temperatura del agua es mayor que la del hierro