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planteas la ecuacion asi:
x=numero menor
x+1=numero medio
x+2=numero mayor
x+x+1+x+2=312
3x+3=312
3x=312-3
3x=309
x=309/3
x=103
reemplazamos:
x=numero menor=>103
x+1=numero medio=>103+1=104
x+2=numero mayor=>103+2=105
espero ayude