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Sea C el punto intermedio buscado.
Según el enunciado es AC = 2 CB
AB = AC + CB = AC + 1/2 AC = 3/2 AC
El vector posición de C es OC = OA + AC = OA + 2/3 AB
AB = OB - OA = (1, 4) - (4, - 3) = (- 3, 7)
OC = (4, - 3) + 2/3 (- 3, 7) = (4, - 3) + (- 2; 14/3) = (2, 5/3)
Se adjunta un gráfico.
Saludos Herminio