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[(4x+1)/2] [(6x-5)/2] = [(x+1)(8x-5) / 4]
[(4x+1)(6x-5)] / 4=[(x+1)(8x-5)] / 4......simplificando 4
(4x+1)(6x-5) = (x+1)(8x-5)
24x∧2 -20x + 6x - 5 = 8x∧2 - 5x + 8x - 5 ....por propiedad distributiva
16x∧2 - 14 x = 3x.........eliminando por términos semejantes
16x∧2∧-∧ 17x = 0
x (16x - 17) = 0......factorizando
Luego igualando a cero ambos factores:
x_1 = 0
16x - 17= 0
16x= 17
x_2 = 17/16 Rpta.