Question

Aplicar propiedad distributiva y verificar
3(x+2)+2(x+1)=13
porfa ayuden

Answer 1

3 (x + 2) + 2 (x + 1) = 13

3x + 6 + 2x + 2 = 13

5x + 8 = 13

5x = 13 - 8

5x  =5

x = 5/5

x = 1

Solución : 

x = 1

VERIFICAMOS : 

3 (x + 2) + 2 (x + 1) = 13

3 (1 + 2) + 2 (1 + 1) = 13

3 (3) + 2 (2) = 13

9 + 4 = 13

13 = 13

Listo.