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[(2x+1)/3]^3 = 5^3
[(2x+1)/3] = 5
2x + 1 = 5.3
2x = 15 - 1
x= 14/2
x= 7
El numero es 7
Verificamos:
[(2(7)+1)/3]^3 = 125
[(14+1)/3]^3 = 125
[15/3]^3 = 125
[5]^3 = 125
125 = 125