Question

Apabila x1 dan x2 akar-akar persamaan kuadrat x^2+2x-3=0 maka nilai dari x1^2+x2^2 =

Answer 1

Verified answer

X² + 2x - 3 = 0
(x - 1)(x + 3) = 0
x = 1 atau x = -3

x1² + x2²
= 1² + (-3)²
= 1 + 9
= 10

Answer 2

X²+2x-3=0
.
a=1, b=2, c=-3
.
=> x1+x2= -b/a = -2
=> x1.x2= c/a = -3
.
nilai dari x1²+x2²=
> (x1+x2)²-2x1.x2
> (-2)²-2.(-3)
> 4+6= 10

semoga membantu:)))