Question

Aljabar!
Tentukan hasil pembagian berikut!
a. (P² - 9) : (P + 3); P = -3
b. (3x² - x - 4) : (x + 1); p = -3
c. (p² + 2p + 1) : (p + 1); x = -1
d. (m² - 2m + 1) : (m - 1); m = 1

Answer 1

A. (P² - 9) : (P + 3); P = -3
=(p-3)(p+3)/(p+3)
=(p-3)
=(-3-3)
=-6
b. (3x² - x - 4) : (x + 1); x = -3
=((-3)²-(-3)-4)/(-3+1)
=(9+3-4)/(-2)
=8/(-2)
=-4
c. (p² + 2p + 1) : (p + 1); p = -1
=(p+1)(p+1)/(p+1)
=(p+1)
=(-1+1)
=0
d. (m² - 2m + 1) : (m - 1); m = 1
=(m-1)(m-1)/(m-1)
=(m-1)
=(1-1)
=0