" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Q=56A*3600s*50%/100%=100800 C(kulombów)
2. Obliczam przyrost masy anody(ujemnej)
mPb=207u
mPbSO4=303u
Pb + SO4(2-)---->PbSO4 + 2e
2*96485 C----(303 - 207)g
100800 C------xg
x≈50,2g
3. Obliczam przyrost masy katody(dodatniej)
mPbO2=239u
mPbSO4=303u
PbO2 + SO4(2-) + 2e + 4H(+)---->PbSO4 + 2H2O
2*96485 C----(303 - 239)g
100800 C------xg
x≈33,5g