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a= 1 b=-2 c=-3
x1+x2 = -b/a = 2
x1.x2 = c/a = -3
x²-(α+β)x+αβ=0
x²-(x1+2+x2+2)x+(x1+2) (x2+2) = 0
x²-((x1+x2)+4)x+(x1.x2)+2(x1+x2)+4=0
x²-(2+4)x + (-3)+2(2)+4=0
x²-6x+5=0