ImmanuelSinaga
2 votes
Thanks 0
lovekillu
maaf gak ada jawabannya di option
A. 4
B. 9
C. 16
D. 25
E. 36
lovekillu
tolong di perbaiki dong
ImmanuelSinaga
soalnya seperti itu gak? :D
lovekillu
iya yg ditanya a² adalah.... (soalnya yg ditanya seperti itu)
ImmanuelSinaga
ada kesalahan pada optionnya dek ^_^
Takamori37
![$\begin{align}\frac{a^{1/2}a^{1/3}}{a^{2/3}}&=\frac1{8^{-2}} \\ a^{1/2}\times a^{\textstyle \frac13-\frac23}&=\left[\frac18\right]^{-2} \\ a^{1/2}\times a^{-1/3}&=(8^{-1})^{-2} \\ a^{\textstyle \frac12+(-\frac13)}&=8^{-1\times(-2)} \\ a^{(3-2)/6}&=8^2 \\ a^{1/6}&=8^2 \\ (a^{1/6})^6&=(8^2)^6 \\ a&=8^{12} \\ a^2&=8^{12\times2} \\ a^2&=8^{24}\end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D%5Cfrac%7Ba%5E%7B1%2F2%7Da%5E%7B1%2F3%7D%7D%7Ba%5E%7B2%2F3%7D%7D%26%3D%5Cfrac1%7B8%5E%7B-2%7D%7D+%5C%5C+a%5E%7B1%2F2%7D%5Ctimes+a%5E%7B%5Ctextstyle+%5Cfrac13-%5Cfrac23%7D%26%3D%5Cleft%5B%5Cfrac18%5Cright%5D%5E%7B-2%7D+%5C%5C+a%5E%7B1%2F2%7D%5Ctimes+a%5E%7B-1%2F3%7D%26%3D%288%5E%7B-1%7D%29%5E%7B-2%7D+%5C%5C+a%5E%7B%5Ctextstyle+%5Cfrac12%2B%28-%5Cfrac13%29%7D%26%3D8%5E%7B-1%5Ctimes%28-2%29%7D+%5C%5C+a%5E%7B%283-2%29%2F6%7D%26%3D8%5E2+%5C%5C+a%5E%7B1%2F6%7D%26%3D8%5E2+%5C%5C+%28a%5E%7B1%2F6%7D%29%5E6%26%3D%288%5E2%29%5E6+%5C%5C+a%26%3D8%5E%7B12%7D+%5C%5C+a%5E2%26%3D8%5E%7B12%5Ctimes2%7D+%5C%5C+a%5E2%26%3D8%5E%7B24%7D%5Cend%7Balign%7D "$\begin{align}\frac{a^{1/2}a^{1/3}}{a^{2/3}}&=\frac1{8^{-2}} \\ a^{1/2}\times a^{\textstyle \frac13-\frac23}&=\left[\frac18\right]^{-2} \\ a^{1/2}\times a^{-1/3}&=(8^{-1})^{-2} \\ a^{\textstyle \frac12+(-\frac13)}&=8^{-1\times(-2)} \\ a^{(3-2)/6}&=8^2 \\ a^{1/6}&=8^2 \\ (a^{1/6})^6&=(8^2)^6 \\ a&=8^{12} \\ a^2&=8^{12\times2} \\ a^2&=8^{24}\end{align}")
1 votes
Thanks 0
lovekillu
maaf optionnya ini...
A. 4
B. 9
C. 16
D. 25
E. 36
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