___________________________________________
a.
BD = √AB² + BC²
BD = √3² + 4²
BD = √9 + 16
BD = √25
BD = 5 cm
b.
CG = DH
HB = √DH² + BD²
HB = √5² + 5²
HB = √25 + 25
HB = √50 cm
Penjelasan dengan langkah-langkah:
BANGUN RUANG BALOK
AB = 3 cm → p
BC = 4 cm → l
CG = 5 cm → t
a) BD = diagonal alas
BD = √(p² + l²)
BD = √(3² + 4²)
BD = √[(3+4)² – 2(3)(4)]
BD = √(7² – 6×4)
BD = √(49 – 24)
b) HB = diagonal ruang
HB = √(BD² + CG²)
HB = √(5² + 5²)
HB = √(5² × 2)
HB = √(5)² × √2
HB = 5 × √2
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SOAL 1
___________________________________________
a.
BD = √AB² + BC²
BD = √3² + 4²
BD = √9 + 16
BD = √25
BD = 5 cm
___________________________________________
b.
CG = DH
HB = √DH² + BD²
HB = √5² + 5²
HB = √25 + 25
HB = √50 cm
___________________________________________
Penjelasan dengan langkah-langkah:
BANGUN RUANG BALOK
AB = 3 cm → p
BC = 4 cm → l
CG = 5 cm → t
a) BD = diagonal alas
BD = √(p² + l²)
BD = √(3² + 4²)
BD = √[(3+4)² – 2(3)(4)]
BD = √(7² – 6×4)
BD = √(49 – 24)
BD = √25
BD = 5 cm ✔
b) HB = diagonal ruang
HB = √(BD² + CG²)
HB = √(5² + 5²)
HB = √(5² × 2)
HB = √(5)² × √2
HB = 5 × √2
HB = 5√2 cm ✔