a(b-c)
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d+f = g(d+f)
obliczyc:d i c
Obliczanie d:
a(b - c) / (d+f) = g(d+f)
a(b - c) = g(d+f)²
(d+f)² = a(b - c)/g
|d + f| = √[ a(b-c)/g ]
d = ± √[ a(b-c)/g ] - f
Obliczanie c:
b - c = g(d+f)² / a
c = b - g(d+f)² / a
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Obliczanie d:
a(b - c) / (d+f) = g(d+f)
a(b - c) = g(d+f)²
(d+f)² = a(b - c)/g
|d + f| = √[ a(b-c)/g ]
d = ± √[ a(b-c)/g ] - f
Obliczanie c:
a(b - c) / (d+f) = g(d+f)
a(b - c) = g(d+f)²
b - c = g(d+f)² / a
c = b - g(d+f)² / a