Wiadomo, ze a>0 i b<0 i 3b^2 = 3a^2 + 8ab. Oblicz wartosc wyrazenia (3a-2b)/(a+2b)
3b²-3a²-8ab=0
3b²-3a²+ab-9ab=0
b(3b+a)-3a(a+3b)=0
(3b+a)(b-3a)=0
a=-3b v b=3a∉D bo a i b sa roznych znakow
stad a=-3b
(3a-2b)/(a+2b)=[3*(-3b)-2b]/(-3b+2b)=-11b:(-b)=11
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3b²-3a²-8ab=0
3b²-3a²+ab-9ab=0
b(3b+a)-3a(a+3b)=0
(3b+a)(b-3a)=0
a=-3b v b=3a∉D bo a i b sa roznych znakow
stad a=-3b
(3a-2b)/(a+2b)=[3*(-3b)-2b]/(-3b+2b)=-11b:(-b)=11