Berapa hasil dari a log 1/b . b log 1/c^2 . c log 1/a^2
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MathSolver74
A'log b⁻¹ . b'log c⁻² . c'log a⁻² = (-1)(-2)(-2) a'log b . b'log c . c'log a = - 4
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bezjnZepiejnZ80
A log 1/b × b log 1/c^2 × c log 1/a^2 = a log b^-1 × b log c^-2 × c log a^-2 = -1 × a log b × -2 × b log c × -2 × c log a = -1 × -2 × -2 × a log b × b log c × c log a = -4 × a log a = -4 × 1 = -4
= (-1)(-2)(-2) a'log b . b'log c . c'log a
= - 4
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