a)√121-√162+√200=
b)√72+4√18+√8=
c)(4√3+√12-√75)*√3=
proszę o pomoc daję naj..
a) √121-√162+√200= 11+√2
b) √72+4√18+√8= 20√2
(4√3+√12-√75)*√3=3
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a) √121-√162+√200= 11+√2
b) √72+4√18+√8= 20√2
(4√3+√12-√75)*√3=3