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= 4log15
= 3log15 / 3log4
= 3log(3*5) / 3log4
= (3log3 + 3log5) / 3log4
= (1 + 3log5) / 3log4)
= (1 + b) / (1/a)
= a+ab
= a(1+b)
2.
4 log 39
4² = 16
4³ = 64
berarti 4log39 diantara 2 dan 3
3.
= 15log40
= 5log40 / 5log15
= 5log(2³ * 5) / 5log(3*5)
= (5log2³ + 5log5) / 5log3 + 5log5
= (3 ^5log2 + 1) / (5log3 + 1)
= (3/b) +1) / (a+1)
= (3 + b) / b(a + 1) isinya yang A