Question

A) 6 (1- jedna trzecia x) =2 (1+jedna druga x) b)-2 (x + jedna druga) -3 (x+jedna trzecia)=0
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Answer 1

a)

6-2x  = 2+x

-2x-x = 2-6

-3x = -4 |: (-3)

x = 4/3 = 1 1/3

 

b)

-2x-1-3x-1 = 0

-2x-3x = 1+1

-5x = 2 |: (-5)

x = -2/5

Answer 2

a)

6(1-1/3x) = 2 (1 + 1/2x)

6 - 2x = 2 + x

-2x-x=2-6

-3x=-4      /:(-3)

x=4/3

 

b)

-2(x+1/2)-3(x+1/3)=0

-2x-1 -3x-1=0

-5x=2   /:(-5)

x= - 2/5