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3'log (x-1)(x+5) = 3'log 3^3 dengan x > 1 atau x > - 5 --> x > 1
x^2 + 4x - 5 = 27
x^2 + 4x - 32 = 0
(x+8)(x-4)= 0
x = - 8 (TM)
x = 4
.
b) 2'log (3x+7) = 5'log (3x-7)
basis berbeda --> 2'log 1 = 5'log 1
maka
3x+7 = 1
3x = -6
x = -2