Question

27 log 2 = x, maka 32 log 1/9 =...

Answer 1

27log 2 = x
(3^3)log 2 = x
(1/3).3log 2 = x
3log 2 = 3x
2log 3 = 1/(3x)

32 log (1/9) = (2^5)log (3^(-2))
                     = (-2/5) . 2log 3
                     = (-2/5) . 1/(3x)
                     = -2/15x
                     =