Question

1.Oblicz:

a)(2-1/7)*3/2+0,6

b)(2*5/6)^2-(3^2-√1i 7/9)

c)((-2/3)^2/8/9)⁻¹

Answer 1

a)

(2-1/7)*3/2+0,6=(1 i 6/7)*3/2 + 0,6 =

=13/6 * 3/2 + 0,6 =13/4 + 0,6 =3,25 + 0,6  = 3,85

 

b)

(2*5/6)^2-(3^2-√1i 7/9) = (5/3)² - (3² - √1i7/9) =

= 25/9 – (9 - √16/9) = 25/9 – (9 – 4/3) = 25/9 –(9- 1i1/3)

= 25/9 – 7i2/3 = 25/9 -23/3 = 25/9 – 69/9 = - 44/9 = 4i8/9

 

c)

((-2/3)²/8/9)⁻¹ = ( 4/9 : 8/9)¯¹ = (4/9 *9/8)¯¹ = (1/2)¯¹ = 1: ½ = 1 * 2/1 = 2