Na tychmiast potrzebne
Rozwiąż algebraicznie układy równań:
(y-x²=5-4x
(y+2x²+5=7x
(to jest klamra
(
Rozwiązanie:
(x=5/3 v (x=2
(y=10/9 v (y=1
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(y-x²=5-4x
(y+2x²+5=7x
y=x²-4x+5
x²-4x+5+2x²+5-7x=0
y=x²-4x+5
3x²-11x+10=0
Δ=121-4*3*10=1
√Δ=1
x1=(11-1)/6=10/6=5/3
x2=(11+1)/6=2
y1=(5/3)²-4*5/3+5=10/9
y2=2²-4*2+5=1
x1=5/3
y1=10/9
x2=2
y2=1