6(x-2)+10>-20 =
9(3-x)-15<5(2+x) =
Bardzo prosze o obliczenia na dzis z góry dzieki
a)6(x-2)+10>-206x - 12 + 10 > -206x > -20 + 12 - 106x > -18 /:6x > -3b)9(3-x)-15<5(2+x) 27 - 9x - 15 < 10 + 5x-9x - 5x < 10 + 15 - 27-14x < -2 /:(-14)x > 1/7
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a)
6(x-2)+10>-20
6x - 12 + 10 > -20
6x > -20 + 12 - 10
6x > -18 /:6
x > -3
b)
9(3-x)-15<5(2+x)
27 - 9x - 15 < 10 + 5x
-9x - 5x < 10 + 15 - 27
-14x < -2 /:(-14)
x > 1/7