zapisz w najprostrzej postaci
(4a+3)-(2a-4)
-y+(5-y)-3
(4a-2)+(4a+2)
10a-(6a+1)+7(6-a)
5(x+y)-9y-4(y-x)+x
7-[4-(a+2)+6a]*3
wykonaj dzielenia
(18a{kwadrat}b{kwadrat}+48a{kwadrat}b-36ab{kwadrat})/6b
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W załączniku.
zad
(4a+3)-(2a-4)=4a+3-2a+4=2a+7
-y+(5-y)-3=-y+5-y-3=-2y+2
(4a-2)+(4a+2)=16a²-4
10a-(6a+1)+7(6-a)=10a-6a-1+42-7a= -3a+41
5(x+y)-9y-4(y-x)+x=5x+5y-9y-4y+4x+x=10x-8y
7-[4-(a+2)+6a]*3=7-(4-a-2+6a)·3=7-(12-3a-6+18a)=7-12+3a+6-18a=-15a+1
zad2
[18a²b²+48a²b-36ab²]:6b=3a²b+8a²-6ab