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L=2πr
L=π
2πr=π [/:2π]
r=1/2
l=2πr
L=2
2πr=2 [/:2π]
r=1/π
L=2πr
L=10π
2πr=10π [/:2π]
r=5
L=2πr
L=0,6π
2πr=0,6π [:2π]
r=0,3
L=2πr
L=6,28
2πr=6,28 [/:2π]
r=3,14/π
zad 3 str 63
P= a) r=?r= b) c) d) r= 1kme) r =
zad 9 str 64
TT=3,14czyli O=TTr kwadrata. 16TT : 2 = 8TTr=8TTO=TTx8TTkwadrat=TTx64TT=64cm (bo TT sie skracają) b.O=TTr kwadratO=TTx1/2TTkwadrat=TTx1/4TT=1/4 (bo TT się skracają)
teszte z tego zadania nie wiem