1)
2x-2 / x-1 = 0
D:
x-1 ≠0
x=1
x∈R\{1}
rownanie będzie = 0 jezeli licznik = 0, więc:
2x-2 = 0
2x = 2
x=1 nie nalezy do D ,
brak rozwiązania
2)
D: x+4 ≠0
x≠-4
x∈R\{-4}
x-2/x+4 - 5/6 = 0
x-2/x+4 = 5/6
5(x+4) = 6(x-2)
5x+20 = 6x - 12
5x-6x = -12-20
-x = -32
x=32 nalezy do D
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1)
2x-2 / x-1 = 0
D:
x-1 ≠0
x=1
x∈R\{1}
rownanie będzie = 0 jezeli licznik = 0, więc:
2x-2 = 0
2x = 2
x=1 nie nalezy do D ,
brak rozwiązania
2)
D: x+4 ≠0
x≠-4
x∈R\{-4}
x-2/x+4 - 5/6 = 0
x-2/x+4 = 5/6
5(x+4) = 6(x-2)
5x+20 = 6x - 12
5x-6x = -12-20
-x = -32
x=32 nalezy do D