5do potęgi logx - 3do potęgilogx-1 > 3do potęgi logx+1 - 5do potęgi logx-1 Oblicz x.
5^(logx) + 5^(logx-1) > 3^(logx+1)+3^(logx-1)
5^(logx)+ 1/5 * 5^(logx) > 3*3^(logx) + 1/3 * 3^(logx)
6/5 * 5^(logx) > 10/3 * 3^(logx)
dzielę przez 3^(logx)
6/5 * (5^(logx) / 3^(logx) ) > 10/3 *5/6
(5/3)^(logx) > 50/18
(5/3)^ (logx) > 25/9
(5/3)^ (logx) >(5/3)^2
logx>2
logx>2log10
logx>log(10^2)
x>100
zalacznik
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5^(logx) + 5^(logx-1) > 3^(logx+1)+3^(logx-1)
5^(logx)+ 1/5 * 5^(logx) > 3*3^(logx) + 1/3 * 3^(logx)
6/5 * 5^(logx) > 10/3 * 3^(logx)
dzielę przez 3^(logx)
6/5 * (5^(logx) / 3^(logx) ) > 10/3 *5/6
(5/3)^(logx) > 50/18
(5/3)^ (logx) > 25/9
(5/3)^ (logx) >(5/3)^2
logx>2
logx>2log10
logx>log(10^2)
x>100
zalacznik