August 2018 1 40 Report
1)
a)-3³:|-3|-2×|-4)=
b)(-3a²b)²=
c)(-ab²cd²)⁵=
d)[(½ab)³×(2ab²)²]⁵=
e)[(½ab)³×(2ab²)²]³=
f)(¹/₄₂)³:(-¹/₂₁)³-100³×(-¹/₁₀)³=
2)
a)(√100)²-(³√-0,008)³-⅓×(√3)²+(2√1,5)²-0,008=
b)(³√-1,25׳√-100)³-(√2×√3×√5)²+(0,2×√5080)³=
c)3√2-7√2+2√2+2=
d)√32:√2-³√⅔׳√⁵/₁₆=

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