podane wyrazenie doprowadz do najprostrzej postaci i oblicz
A) (2x-5y)(3x+4y)-6(x+2y)² dla x=¾ i y=⅔
b)(2x+y)²-(x+3)(x-3)-(y²+9) dla x=-2 i y=½
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A) (2x-5y)(3x+4y)-6(x+2y)= po pos=dstawieniu mamy
-44*2/3*2/3-31*2/3**3/4= -179/9-31/2=-352/18-279/18=-631/18=-35 i 1/18
B) (2x+y)^{2}-(x+3)(x-3) podstawiamy
3*(-2)*(-2)+4*(-2)*1/2=12+4=16
A) (2x-5y)(3x+4y)-6(x+2y)^2 = 6x^2 +8xy -15xy -20y^2 -6x^2 -24 xy -24y^2 =
= - 31xy -44y^2 = -31*3/4*2/3 - 44 *2/3^2 = -31*1/4*2/1 -44* 4/9=
= -31 * 2/4 - 176/9 = -62/4 -176/9 = - 558/36 - 704/36= -1262/36=- 35i 2/36=
= - 35 i 1/18
B) (2x+y)^2 -(x+3)(x-3)-(y^2+9) = 4x^2 +4xy +y^2-x^2+3x -3x+9 -y^2 -9 =
= 3x^2 + 4xy = 3*(-2)^2 +4*(-2)*1/2= 3*4 +(-8)*1/2 = 12 -8/2=12-4 = 8