Question

oblicz stosujac prawa działan na potegach :

a) (2,6)^-4 * (2,6)^3

b) (4^-5)^-2 : 4^9

c) [(2 1/5) ^-3] * (2 1/5)^7

Answer 1

,a)

 =(2,6)^(-4+3)=(2,6)^-1=(26/10)^-1=13/5)^-1=5/13

b)

=4^(10-9)=4^1=4

c)

= (11/5)^(-3+7)=(11/5)^4=14641/625=23  266/625