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a)5(x+1)+7(x-1)-3(x^2+x)=5x+5+7x-7-3x^2-3x= -3x^2+9x-2
b) 2(3x^2 - 3)+(2x+1)(2-x)= 6x^2-6+4x-2x^2+2-x = 4x^2+3x+-4
c) 7x(1/7x-6/7)-1/5(5x+5)(x-1)=x^2-6x-1/5(5x^2-5x+5x-5)=x^2-6x-x^2+1=-6x+1
d) (5x-2)(3x-1)-3(x-1)(2x+3)= 15x^2-5x-6x+2-3(2x^2+3x-2x-3)=15x^2-5x-6x+2-6x^2-3x+9=9x^2-14x+11
Pozdrawiam ;-)