1.Usuń niewymiernośc z mianownika.
a)2/√3
b)4/3√2
c)1/6+√2
d)2√2/√5+4
e)2/4-3√2
f)2√3-1/2√3+2
g)1/√3-√2
h)√3/√5+√3
2.Wyprowadz wzory skróconego mnożeni.
(a+b)²=(a+b) x (a+b)=
(a-b)²=(a-b) x (a-b)=
(a-b)(a+b)=
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1.
a)
b)
c)
d)
e)
f)
g)
h)
2.
Myślę, że dobrze rozwiązałem.