(5√2-1)(5√2+1)=
(2√2-1)²=
(2√3+3)(3-2√3)=
(5√2-1)²(2√2+1)=
Usuń niewymiernośc z mianownika;
5 nad √2+1=
√3 nad 2-√3=
3√2 nad 2√2-1=
√3+√5 nad √3-√5=
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(5√2-1)(5√2+1)=50-1=49
(2√2-1)²=8-4√2+1
(2√3+3)(3-2√3)=(3+2√3)(3-2√3)=9-12=-3
(5√2-1)²(2√2+1)=(50-10√2+1)(2√2+1)=(51-10√2)·(2√2+1)=102√2+51-40-10√2=11+92√2
Usunięcie niewymierności w załączniku
Pozdrawiam:)