Question

2+(x-4)(x+4)=(x-1)^2
4(x+7)(x+6)-(2x+3)^2+1=0
1/2y+2y+1/5-y-1/3(1-y)=8-3y/6
x-3/2=6x-3/5

Answer 1

2+(x-4)(x+4)=(x-1)^2

2+x²-16=x²-2x+1
-14-1=-2x
2x=15
x=7,7

4(x+7)(x+6)-(2x+3)^2+1=0

4*(x²+6x+7x+42)-(4x²+12x+9)+1=0
4x²+52x+168-4x²-12x-9+1=0
40x=-160
x=-40




x-3/2=6x-3/5 /*(10)

10x-15=60x-6
-50x=9
x=-9/50