(4/3)^-5*(3/5*4/5)+√1-(3/5)^ jeden-3/5 kwadrat pierwiastek na całości
(4/3)^-5(3/5*4/5)+(pierw.z 1-3/5)^=
= 16/9 - 24/10 + 2/5=
=160/90 - 216/90 + 36/90=
=- 20/90=
=- 2/9
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(4/3)^-5(3/5*4/5)+(pierw.z 1-3/5)^=
= 16/9 - 24/10 + 2/5=
=160/90 - 216/90 + 36/90=
=- 20/90=
=- 2/9