Question

OBLICZCIE MI TO BŁAGAM WAS :


(0,75) ^{-1} * (2 \frac{10}{27}) ^ {-\frac{2}{3} * (2,5) ^{2}=

(6,25) ^ {0,5} * (0,01) ^ {-1} =

( _{} \frac{25}{49} ^{1/2} * ( _{} \frac{2}{7}) ^ {-1} =
5 ^ {1} * 25 ^ {1/2} =
9 ^ {-1,5} =
27 ^ {-4/3} =
x ^ {} \frac{1}{3} =
3\sqrt[3]{3} =
x ^{-1/5} =
3\frac{3}{8} =




PROSZEEEE, ŻEBY KTOŚ MI TO ZROBIŁ !

Answer 1

Rozwiązuję tak jak odczytałem.
0,75^-1 * (2 10/27)^-2/3 * 2,5^2=(3/4)^-1 *(64/27)^-2/3 * (25/10)^2=
=4/3 *(27/64)^2/3 *(25/10)^2=4/3*(3/4)^2 * (5^4)/2^2*5^2=(3*5^4)4*2^2*5^2=3*5^2/4*4=
=3*25/16=75/16=6 11/16

(6,25)^0,5*(0,01)^-1=2,5*100=250

(25/49)^1/2*(2/7)^-1=5/7*7/2=5/2

5^1*25^1/2=5^1*(5^2)^1/2=5*5=25

9^-1,5=(3^2)^-1,5=3^-3=(1/3)^3=1/27

27^-4/3=(3^3)^-43=3^-4=(1/3)^4=1/81

x^1/3=Vx

3 _[3]V3=3^1*3^1/3=3^(1+ 1/3)=3^4/3

3V3=3^1*3^1/2=3^(1+1/2)=3^3/2

x^-1/5=(1/x)1/5=_[5]V(1/x)

3 3/8=27/8=(3/2)^3