Question

A-2(b-1)+2[-5(a+1)-0,5a]+2b= dla a=4/5 i b=1/4

Answer 1

Dla a=4/5 i b=1/4

a-2(b-1)+2[-5(a+1)-0,5a]+2b=
a-2b+2+2(-5a-5-0,5a)+2b=
a-2b+2-10a-10-a+2b=
-10a-8=-10*4/5-8=-8-8=-16

Answer 2

A-2(b-1)+2[-5(a+1)-0,5a]+2b= dla a=4/5 i b=1/4

a-2(b-1)+2[-5(a+1)-0,5a]+2b=a-2b+2+2a2a2(-1a)+2b=2a+4

2*4/5+4=2,5

Answer 3

=⅘-2(¼-1)+2[-5(⅘+1)-½×⅘]+2×¼=⅘-½+2+2(-5×⁹/₅-⅖)+½=⅘+³/₂+2(-9-⅖)+½=²³/₁₀+2(-⁴⁷/₅)+½=²³/₁₀-¹⁸⁸/₁₀+⁵/₁₀= -¹⁶⁰/₁₀=-16