September 2018 1 16 Report

[tex]a_n=({\frac{n+1}{n-2})^{2n-1}[/tex]

Wynik e^6

a_n=\sqrt{\frac{3n-2}{n+10}

Wynik powinien wynosic √3

a_n=\frac{5*3^{2n}-1}{4*9^{n}+7

Wynik 5/4


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