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FeS..........+...........2HCl ---------> FeCl2..........+............H2S
88g.....................................................................22,4 dm3
44g.......................................................................x
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x = 44g *22,4dm3 /88g = 11,2dm3 H2S gdyby wydajność 100%
11,2dm3.....................100%
..y.............................85%
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y = 85% *11,2dm3 /100% = 9,52 dm3 H2S otrzymano w tej reakcji.
Semper in altum.................................pozdrawiam :]
FeS + 2HCl------>FeCl2 + H2S
88g FeS-------------22,4 dm3 H2S
44g FeS--------------xdm3 H2S
x=44*22,4/88
x=11,2dm3 H2S
11,2dm3 H2S------100%
xdm3 H2S----------85%
x=85*11,2/
x=9,52dm3 H2S