Question

Dodawanie i odejmowanie ułamków

a)Od sumy ułamków 3 3/4i1 1/3 odejmij różnicę ułamków 2 1/2i 5/6

b)Od liczby 10 odejmij sumę różnicy ułamków 2.5 i 2/3 i różnicy ułamków 5.6 i 2 2/4

Answer 1

a) 3 3/4 + 1 1/3= 3 12/12 + 1 4/12= 4 16/12 = 5 4/12

5 4/12 - (2 1/2 - 5/6) = 5 4/12 - (2 6/12 - 10/12) = 5 4/12 - (18/12 - 10/12) =   = 5 4/12 - 8/12 = 3 12/12 - 8/12 = 3 4/12

 

a b nie wiem jak zrobić ;p

Answer 2

a) (3 3/4 +1 1/3) - (2 1/2 - 5/6) = ( 15/4 + 4/3) - (5/2 - 5/6) = (45/12 + 16/12) - (15/6 - 5/6) = 61/12 - 10/6 = 61/12 - 20/12 = 41/12 = 3 5/12

b) 10 - [(2 1/2 - 2/3) + (5 6/10 - 2 2/4)] = 10 - [( 5/2 - 2/3) + (5 3/5 - 2 1/2)] = 10 - [(45/6 - 4/6) + (28/5 - 5/2)] = 10- [41/6 + (56/10 - 25/10)] = 10 - [41/6 + 31/10] = 10- [205/30 + 93/30] = 10 - 298/30 = 10 - 9 28/30 = 2/30 = 1/15

Answer 3

a)( 3 3/4+ 1 1/3)- (2 1/2-5/6)=(45/12+16/12)-(30/12-10/12)=61/12-20/12=41/12=36 5/12

b)10-((2 1/2-2/3)+(5 6/10-2 2/4))= 10-((15/6-4/6)+(112/20-50/20)=10-(11/6+62/20)=10-(110/60+186/60)=10-296/60=600/60-296/60=304/60=       5 1/15