Rozwiąż.
\sqrt{8}+\sqrt{2} : \sqrt{2} (tylko, że zamiast podzielić to jest kreska ułamkowa)
\sqrt{4 do potęgi2 +3 do potęgi2} -(3-2 i 1/4) x (-2)
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(√8+√2 )/√2 =(√4·√2+√2)/√2 =(2√2+√2)/√2 =(3√2)/√2 =3
√(4²+3²) -(3-2¼)·(-2)= √(16+9)- ¾ ·(-2)= √25 - (-⁶/₄ )=5+ ³/₂ =5+1½=6½