prosze o pomoc w rozwiazaniu ... wiem ze banalne ale wszytsko pozapominalam ;/
4 do potegi 3 + 4 do potegi 2
2 do potegi 10 - 2 do potegi 5
6 do potegi 3 + 6
b do potegi 5 + b do potegi 3
2c do 3 + 3c do 3
e do 2 + e do 3
3f do 2 *2f do 3
4g do 3 * 5g do 2
(3j) do 2
(2k do 3) do 2
(7l do 6) do 2
(m do 2 n ) do 3
(p do 2 q do 4) do 3
(3rs) do 2
v do 2 w *vw do 2
prosze o wytlumaczenie
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4^3 + 4^2 =4 x 4^2 +4^2 =4^2(4+1) =80
2^10 -2^5 =2^5 x 2^5 -2^5 =2^5(2^5-1) =32(32-1) =32x31 = 992
6^3+6 =6x6^2 +6 =6(6^2+10 =6x37 =222
b^5 +b^3 =b^2 x b^3 +b^3 =b^3(b^2+1)
2c^3 +3c^3 =5c^3
e^2 +e^3 =e^2 +e x e^2 =e^2(1+e)
3f^2 x 2f^3 =6f^5
4g^3 x 5g^2 =20g^5
(3j)^2 =9j^2
(2k^3)^2 =4k^6
(7l^3)^2 =49l^6
(m^2 n)^3 =m^6 n^3
(p^2 q^4)^3 =p^6 q^12
(3rs)^2 =9r^2 s^2
v^2w x vw^2 =v^3 w^3
Mnożąc potęgi o tych samych podstawach dodajemy ich wykładniki.
Potęgując potęgi o tych samych podstawach,mnożymy ich wykładniki.
(^ do potęgi)