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b) (24a³b³c²):(8ab²c)= 3a²bc
c)(2/3x³y)/(1/3x³y)= 2
a) (- 4xyz) * ( - 1/2x"yz) =
(-4xyz)*(-1/2x²yz) = 4/2x³y²z² = 2x³y²z²
b) (24a"'b"'c"):( 8ab"c)=
(24a³b³c²)/(8ab²c) = 3a²bc
c) 2/3x"'y"
--------- =
1/3x"'y
(2/3x³y²)/(1/3x³y) = 2x⁰y=2y
drugim 3a''bc
trzecim 2,5xy
nie wiem czy dobrze, ale raczej tak : )