-3x²+2x+5>0
a=-3,b=2,c=5
Δ=b²-4ac=2²-4*(-3)*5=4+60=64 więc:√Δ=√64=8
x∈<-1,1⅔>
liczę na naj ;D
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-3x²+2x+5>0
a=-3,b=2,c=5
Δ=b²-4ac=2²-4*(-3)*5=4+60=64 więc:√Δ=√64=8
x∈<-1,1⅔>
liczę na naj ;D