Question

Rozwiąż równania:
a/ (3x+4)/(x+2) = (x+8)/(x+5)
b/ (x+5)/(2x-6) = (2x-7)/(3x-9)

Answer 1

A/ (3x+4)/(x+2) = (x+8)/(x+5)
b/ (x+5)/(2x-6) = (2x-7)/(3x-9)

Dr: x∈R\{-5,-2}

(3x+4)(x+5)=(x+2)(x+8)

3x²+19x+20=x²+10x+16

2x²+9x+4=0

Δ=81-32=49

x= -9-√49/-4 ∨ x= -9+√49/-4

x=-16/-4 ∨ x= -2/-4

x= 4 ∨ x = 0,5



b/ (x+5)/(2x-6) = (2x-7)/(3x-9)


Dr:x∈R\{3}

x+5/2(x-3) = 2x-7/3(x-3)

x+5/2 = 2x-7/3

3(x+5)= 2(2x-7)

3x+15=4x-14

x=29