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3(2²-2*2+3)-2(2²-5*2-1)
=3(4-4+3)-2(4-10-1)
=3(3)-2(-7)
=9+14
=23
a(2ab+b)-b(a-2ab+a²) dla a=0,1 i b= -10
0,1(2*0,1+-10)-(-10)(0,1-2*0,1*(-10)+0,1²)
=0,1(0,2-10)+10(1,91)
=0,1(-9,8)+19,1
=-0,98+19,1
=18,12
x(2x+2x+1)-(-4x³ +8x²-6):2
=2x²+2x²+1x-(2x³+4x²-3)
=4x²+1x-2x³-4x²+3
=1x-2x³+3
w 2 wyszlo mi -11,1
w 3 wyszlo mi 6xdo potęgi 3 - 6x do potęgi 2 + x+ 3